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# 題目敘述
Given an integer n , break it into the sum of k positive integers, where k >= 2 , and maximize the product of those integers.
Return the maximum product you can get.
# Example 1
Input: n = 2
Output: 1
Explanation: 2 = 1 + 1, 1 × 1 = 1.
# Example 2
Input: n = 10
Output: 36
Explanation: 10 = 3 + 3 + 4, 3 × 3 × 4 = 36.
# 解題思路
# Solution
| class Solution { | |
| public int integerBreak(int n) { | |
| if (n <= 3) | |
| return n - 1; | |
| int quotient = n / 3, remainder = n % 3; | |
| if(remainder == 0){ | |
| return (int) Math.pow(3, quotient); | |
| }else if(remainder == 1){ | |
| return (int) Math.pow(3, quotient - 1) * 4; | |
| }else{ | |
| return (int) Math.pow(3, quotient) * 2; | |
|         } | |
|     } | |
| } | 
單字
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片語 & 搭配詞
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