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# 題目敘述

Given an integer n , break it into the sum of k positive integers, where k >= 2 , and maximize the product of those integers.

Return the maximum product you can get.

# Example 1

Input: n = 2
Output: 1
Explanation: 2 = 1 + 1, 1 × 1 = 1.

# Example 2

Input: n = 10
Output: 36
Explanation: 10 = 3 + 3 + 4, 3 × 3 × 4 = 36.

# 解題思路

# Solution

class Solution {
    public int integerBreak(int n) {
        if (n <= 3)
            return n - 1;
        int quotient = n / 3, remainder = n % 3;
        if(remainder == 0){
            return (int) Math.pow(3, quotient);
        }else if(remainder == 1){
            return (int) Math.pow(3, quotient - 1) * 4;
        }else{
            return (int) Math.pow(3, quotient) * 2;
        }
    }
}


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片語 & 搭配詞

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