⭐️⭐️
# 題目敘述
You are given two strings s
and t
consisting of only lowercase English letters.
Return the minimum number of characters that need to be appended to the end of s
so that t
becomes a subsequence of s
.
A subsequence is a string that can be derived from another string by deleting some or no characters without changing the order of the remaining characters.
# Example 1
Input: s = "coaching", t = "coding"
Output: 4
Explanation: Append the characters "ding" to the end of s so that s = "coachingding".
Now, t is a subsequence of s ("coachingding").
It can be shown that appending any 3 characters to the end of s will never make t a subsequence.
# Example 2
Input: s = "abcde", t = "a"
Output: 0
Explanation: t is already a subsequence of s ("abcde").
# Example 3
Input: s = "z", t = "abcde"
Output: 5
Explanation: Append the characters "abcde" to the end of s so that s = "zabcde".
Now, t is a subsequence of s ("zabcde").
It can be shown that appending any 4 characters to the end of s will never make t a subsequence.
# 解題思路
# Solution
class Solution { | |
public int appendCharacters(String s, String t) { | |
int sIdx = 0, tIdx = 0, sLen = s.length(), tLen = t.length(); | |
while (sIdx < sLen && tIdx < tLen) { | |
if (s.charAt(sIdx) == t.charAt(tIdx)) tIdx++; | |
sIdx++; | |
} | |
return tLen - tIdx; | |
} | |
} |
單字
** **
!! !!
片語 & 搭配詞
!! !!