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# 題目敘述
You are given a 0-indexed m x n
binary matrix grid
.
A 0-indexed m x n
difference matrix diff
is created with the following procedure:
- Let the number of ones in the
ith
row beonesRowi
. - Let the number of ones in the
jth
column beonesColj
. - Let the number of zeros in the
ith
row bezerosRowi
. - Let the number of zeros in the
jth
column bezerosColj
. diff[i][j] = onesRowi + onesColj - zerosRowi - zerosColj
Return the difference matrix diff
.
# Example 1
Input: grid = [[0,1,1],[1,0,1],[0,0,1]]
Output: [[0,0,4],[0,0,4],[-2,-2,2]]
Explanation:
- diff[0][0] = onesRow0 + onesCol0 - zerosRow0 - zerosCol0 = 2 + 1 - 1 - 2 = 0
- diff[0][1] = onesRow0 + onesCol1 - zerosRow0 - zerosCol1 = 2 + 1 - 1 - 2 = 0
- diff[0][2] = onesRow0 + onesCol2 - zerosRow0 - zerosCol2 = 2 + 3 - 1 - 0 = 4
- diff[1][0] = onesRow1 + onesCol0 - zerosRow1 - zerosCol0 = 2 + 1 - 1 - 2 = 0
- diff[1][1] = onesRow1 + onesCol1 - zerosRow1 - zerosCol1 = 2 + 1 - 1 - 2 = 0
- diff[1][2] = onesRow1 + onesCol2 - zerosRow1 - zerosCol2 = 2 + 3 - 1 - 0 = 4
- diff[2][0] = onesRow2 + onesCol0 - zerosRow2 - zerosCol0 = 1 + 1 - 2 - 2 = -2
- diff[2][1] = onesRow2 + onesCol1 - zerosRow2 - zerosCol1 = 1 + 1 - 2 - 2 = -2
- diff[2][2] = onesRow2 + onesCol2 - zerosRow2 - zerosCol2 = 1 + 3 - 2 - 0 = 2
# Example 2
Input: grid = [[1,1,1],[1,1,1]]
Output: [[5,5,5],[5,5,5]]
Explanation:
- diff[0][0] = onesRow0 + onesCol0 - zerosRow0 - zerosCol0 = 3 + 2 - 0 - 0 = 5
- diff[0][1] = onesRow0 + onesCol1 - zerosRow0 - zerosCol1 = 3 + 2 - 0 - 0 = 5
- diff[0][2] = onesRow0 + onesCol2 - zerosRow0 - zerosCol2 = 3 + 2 - 0 - 0 = 5
- diff[1][0] = onesRow1 + onesCol0 - zerosRow1 - zerosCol0 = 3 + 2 - 0 - 0 = 5
- diff[1][1] = onesRow1 + onesCol1 - zerosRow1 - zerosCol1 = 3 + 2 - 0 - 0 = 5
- diff[1][2] = onesRow1 + onesCol2 - zerosRow1 - zerosCol2 = 3 + 2 - 0 - 0 = 5
# 解題思路
# Solution
class Solution { | |
public int[][] onesMinusZeros(int[][] grid) { | |
int lenRow = grid.length; | |
int lenCol = grid[0].length; | |
int[] onesRow = new int[lenRow]; | |
int[] onesCol = new int[lenCol]; | |
int[] zeroRow = new int[lenRow]; | |
int[] zeroCol = new int[lenCol]; | |
for(int i = 0; i < lenRow; i++){ | |
for(int j = 0; j < lenCol; j++){ | |
int num = grid[i][j]; | |
if(num == 0){ | |
zeroRow[i]++; | |
zeroCol[j]++; | |
}else{ | |
onesRow[i]++; | |
onesCol[j]++; | |
} | |
} | |
} | |
int[][] ans = new int[lenRow][lenCol]; | |
for(int i = 0; i < lenRow; i++){ | |
for(int j = 0; j < lenCol; j++){ | |
ans[i][j] = onesRow[i] + onesCol[j] - zeroRow[i] - zeroCol[j]; | |
} | |
} | |
return ans; | |
} | |
} |
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