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# 題目敘述
Given a binary array nums
, you should delete one element from it.
Return the size of the longest non-empty subarray containing only 1
's in the resulting array. Return 0
if there is no such subarray.
# Example 1
Input: nums = [1,1,0,1]
Output: 3
Explanation: After deleting the number in position 2, [1,1,1] contains 3 numbers with value of 1's.
# Example 2
Input: nums = [0,1,1,1,0,1,1,0,1]
Output: 5
Explanation: After deleting the number in position 4, [0,1,1,1,1,1,0,1] longest subarray with value of 1's is [1,1,1,1,1].
# Example 3
Input: nums = [1,1,1]
Output: 2
Explanation: You must delete one element.
# 解題思路
# Solution
class Solution { | |
public int longestSubarray(int[] nums) { | |
int n = nums.length; | |
int left = 0; | |
int zeros = 0; | |
int ans = 0; | |
for (int right = 0; right < n; right++) { | |
if (nums[right] == 0) { | |
zeros++; | |
} | |
while (zeros > 1) { | |
if (nums[left] == 0) { | |
zeros--; | |
} | |
left++; | |
} | |
ans = Math.max(ans, right - left + 1 - zeros); | |
} | |
return (ans == n) ? ans - 1 : ans; | |
} | |
} |
單字
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片語 & 搭配詞
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