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# 題目敘述

Given a binary array nums , you should delete one element from it.

Return the size of the longest non-empty subarray containing only 1 's in the resulting array. Return 0 if there is no such subarray.

# Example 1

Input: nums = [1,1,0,1]
Output: 3
Explanation: After deleting the number in position 2, [1,1,1] contains 3 numbers with value of 1's.

# Example 2

Input: nums = [0,1,1,1,0,1,1,0,1]
Output: 5
Explanation: After deleting the number in position 4, [0,1,1,1,1,1,0,1] longest subarray with value of 1's is [1,1,1,1,1].

# Example 3

Input: nums = [1,1,1]
Output: 2
Explanation: You must delete one element.

# 解題思路

# Solution

class Solution {
    public int longestSubarray(int[] nums) {
        int n = nums.length;
        int left = 0;
        int zeros = 0;
        int ans = 0;
        for (int right = 0; right < n; right++) {
            if (nums[right] == 0) {
                zeros++;
            }
            while (zeros > 1) {
                if (nums[left] == 0) {
                    zeros--;
                }
                left++;
            }
            ans = Math.max(ans, right - left + 1 - zeros);
        }
        return (ans == n) ? ans - 1 : ans;
    }
}


單字

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片語 & 搭配詞

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