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# 題目敘述

Given an integer array nums , return the sum of divisors of the integers in that array that have exactly four divisors. If there is no such integer in the array, return 0 .

# Example 1

Input: nums = [21,4,7]
Output: 32
Explanation:
21 has 4 divisors: 1, 3, 7, 21
4 has 3 divisors: 1, 2, 4
7 has 2 divisors: 1, 7
The answer is the sum of divisors of 21 only.

# Example 2

Input: nums = [21,21]
Output: 64

# Example 3

Input: nums = [1,2,3,4,5]
175 0

# 解題思路

# Complexity

  • Time complexity:
    <!-- Add your time complexity here, e.g. $$O(n)$$ -->

  • Space complexity:
    <!-- Add your space complexity here, e.g. $$O(n)$$ -->

# Solution




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