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# 題目敘述
An integer has sequential digits if and only if each digit in the number is one more than the previous digit.
Return a sorted list of all the integers in the range [low, high] inclusive that have sequential digits.
# Example 1
Input: low = 100, high = 300
Output: [123,234]
# Example 2
Input: low = 1000, high = 13000
Output: [1234,2345,3456,4567,5678,6789,12345]
# 解題思路
# Solution
import java.util.ArrayList; | |
import java.util.Collections; | |
import java.util.List; | |
class Solution { | |
public List<Integer> sequentialDigits(int low, int high) { | |
List<Integer> ans = new ArrayList<>(); | |
for(int i = 1; i <= 9; i++){ | |
int num = i; | |
int next = i + 1; | |
while (num <= high && next <= 9) { | |
num = num * 10 + next; | |
next = next + 1; | |
if(num >= low && num <= high){ | |
ans.add(num); | |
} | |
} | |
} | |
Collections.sort(ans); | |
return ans; | |
} | |
} |
單字
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片語 & 搭配詞
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