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# 題目敘述
You are given an integer array cost
where cost[i]
is the cost of ith
step on a staircase. Once you pay the cost, you can either climb one or two steps.
You can either start from the step with index 0
, or the step with index 1
.
Return the minimum cost to reach the top of the floor.
# Example 1
Input: cost = [10,15,20]
Output: 15
Explanation: You will start at index 1.
- Pay 15 and climb two steps to reach the top.
The total cost is 15.
# Example 2
Input: cost = [1,100,1,1,1,100,1,1,100,1]
Output: 6
Explanation: You will start at index 0.
- Pay 1 and climb two steps to reach index 2.
- Pay 1 and climb two steps to reach index 4.
- Pay 1 and climb two steps to reach index 6.
- Pay 1 and climb one step to reach index 7.
- Pay 1 and climb two steps to reach index 9.
- Pay 1 and climb one step to reach the top.
The total cost is 6.
# 解題思路
# Solution
import java.util.Arrays; | |
class Solution { | |
public int minCostClimbingStairs(int[] cost) { | |
int len = cost.length; | |
int[] dp = new int[len]; | |
Arrays.fill(dp, Integer.MAX_VALUE); | |
dp[0] = cost[0]; | |
dp[1] = cost[1]; | |
for (int i = 1; i < len; i++) { | |
dp[i] = Math.min(cost[i] + dp[i - 1], dp[i]); | |
if (i + 1 != len) { | |
dp[i + 1] = Math.min(cost[i + 1] + dp[i - 1], dp[i + 1]); | |
} | |
} | |
return Math.min(dp[len - 2], dp[len - 1]); | |
} | |
} |
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