⭐️

# 題目敘述

Given two integer arrays nums1 and nums2 , sorted in non-decreasing order, return the minimum integer common to both arrays. If there is no common integer amongst nums1 and nums2 , return -1 .

Note that an integer is said to be common to nums1 and nums2 if both arrays have at least one occurrence of that integer.

# Example 1

Input: nums1 = [1,2,3], nums2 = [2,4]
Output: 2
Explanation: The smallest element common to both arrays is 2, so we return 2.

# Example 2

Input: nums1 = [1,2,3,6], nums2 = [2,3,4,5]
Output: 2
Explanation: There are two common elements in the array 2 and 3 out of which 2 is the smallest, so 2 is returned.

# 解題思路

# Solution

import java.util.Arrays;
class Solution {
    public int getCommon(int[] nums1, int[] nums2) {
        Arrays.sort(nums1);
        Arrays.sort(nums2);
        for(int i = 0, j = 0; i < nums1.length && j < nums2.length; ) {
            if(nums1[i] == nums2[j]) {
                return nums1[i];
            } else if(nums1[i] < nums2[j]) {
                i++;
            } else {
                j++;
            }
        }
        return -1;
    }
}


單字

** **
!! !!

片語 & 搭配詞

!! !!