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# 題目敘述
Given two integer arrays nums1
and nums2
, sorted in non-decreasing order, return the minimum integer common to both arrays. If there is no common integer amongst nums1
and nums2
, return -1
.
Note that an integer is said to be common to nums1
and nums2
if both arrays have at least one occurrence of that integer.
# Example 1
Input: nums1 = [1,2,3], nums2 = [2,4]
Output: 2
Explanation: The smallest element common to both arrays is 2, so we return 2.
# Example 2
Input: nums1 = [1,2,3,6], nums2 = [2,3,4,5]
Output: 2
Explanation: There are two common elements in the array 2 and 3 out of which 2 is the smallest, so 2 is returned.
# 解題思路
# Solution
import java.util.Arrays; | |
class Solution { | |
public int getCommon(int[] nums1, int[] nums2) { | |
Arrays.sort(nums1); | |
Arrays.sort(nums2); | |
for(int i = 0, j = 0; i < nums1.length && j < nums2.length; ) { | |
if(nums1[i] == nums2[j]) { | |
return nums1[i]; | |
} else if(nums1[i] < nums2[j]) { | |
i++; | |
} else { | |
j++; | |
} | |
} | |
return -1; | |
} | |
} |
單字
** **
!! !!
片語 & 搭配詞
!! !!