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# 題目敘述
You are given an array nums of non-negative integers. nums is considered special if there exists a number x such that there are exactly x numbers in nums that are greater than or equal to x .
Notice that x does not have to be an element in nums .
Return x if the array is special, otherwise, return -1 . It can be proven that if nums is special, the value for x is unique.
# Example 1
Input: nums = [3,5]
Output: 2
Explanation: There are 2 values (3 and 5) that are greater than or equal to 2.
# Example 2
Input: nums = [0,0]
Output: -1
Explanation: No numbers fit the criteria for x.
If x = 0, there should be 0 numbers >= x, but there are 2.
If x = 1, there should be 1 number >= x, but there are 0.
If x = 2, there should be 2 numbers >= x, but there are 0.
x cannot be greater since there are only 2 numbers in nums.
# Example 3
Input: nums = [0,4,3,0,4]
Output: 3
Explanation: There are 3 values that are greater than or equal to 3.
# 解題思路
# Solution
class Solution { | |
public int specialArray(int[] nums) { | |
int n = nums.length; | |
for (int x = 0; x <= n; x++) { | |
int count = 0; | |
for (int num : nums) { | |
if (num >= x) { | |
count++; | |
} | |
} | |
if (count == x) { | |
return x; | |
} | |
} | |
return -1; | |
} | |
} |
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