⭐️
# 題目敘述
You are given an array nums
of non-negative integers. nums
is considered special if there exists a number x
such that there are exactly x
numbers in nums
that are greater than or equal to x
.
Notice that x
does not have to be an element in nums
.
Return x
if the array is special, otherwise, return -1
. It can be proven that if nums
is special, the value for x
is unique.
# Example 1
Input: nums = [3,5]
Output: 2
Explanation: There are 2 values (3 and 5) that are greater than or equal to 2.
# Example 2
Input: nums = [0,0]
Output: -1
Explanation: No numbers fit the criteria for x.
If x = 0, there should be 0 numbers >= x, but there are 2.
If x = 1, there should be 1 number >= x, but there are 0.
If x = 2, there should be 2 numbers >= x, but there are 0.
x cannot be greater since there are only 2 numbers in nums.
# Example 3
Input: nums = [0,4,3,0,4]
Output: 3
Explanation: There are 3 values that are greater than or equal to 3.
# 解題思路
# Solution
class Solution { | |
public int specialArray(int[] nums) { | |
int n = nums.length; | |
for (int x = 0; x <= n; x++) { | |
int count = 0; | |
for (int num : nums) { | |
if (num >= x) { | |
count++; | |
} | |
} | |
if (count == x) { | |
return x; | |
} | |
} | |
return -1; | |
} | |
} |
單字
** **
!! !!
片語 & 搭配詞
!! !!